≪要点≫
1次関数y=ax+bのグラフは,y=axのグラフをy軸方向にbだけ平行移動させた直線になります. このグラフでは,x=0のときy=bになります.すなわち,y軸上の点(0, b)を通ります. このbの値を1次関数y=ax+bのグラフの「切片」といいます.
【例1】
次の1次関数の切片を求めてください. y=2x+3 ![]() 切片は3…(答) (右図の赤丸のy座標)
【例2】
次の1次関数の切片を求めてください. y=x−2 ![]() 切片は−2…(答) (右図の赤丸のy座標) |
【問題】
次の図は1次関数 |
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